Complete the square on the following quadratic function into the form \({(x + b)^2} + c\):
\[y = {x^2} + 8x + 2\]
\[y = {(x + 8)^2} - 62\]
\[y = {(x + 4)^2} - 14\]
\[y = {(x + 4)^2} + 2\]
\[y = {x^2} + 6x + 15\]
\[y = {(x + 3)^2} + 6\]
\[y = {(x + 3)^2} - 6\]
\[y = {(x + 6)^2} + 24\]
\[y = {x^2} - 8x - 5\]
\[y = {(x + 8)^2} + 11\]
\[y = {(x - 8)^2} + 21\]
\[y = {(x - 4)^2} - 21\]
Write \({x^2} + 3x + 1\) in the form \({(x + b)^2} + c\). What's the value of b?
3
\[\frac{{3}}{{2}}\]
1
The equation \(2{x^2} + 8x - 3 = 0\) is to be solved by completing the square. Which of the following is a correct step in the solution?
\[{(x + 2)^2} = \frac{{11}}{{2}}\]
\[{(2x + 4)^2} = 17\]
\[{(x + 2)^2} = 7\]