Substitute \({y}\) = 4 into the following equation: 4\({x}\) + 2\({y}\) = 52. What is the value of \({x}\)?
\({x}\) = 11
\({x}\) = 10
\({x}\) = 9
Two simultaneous equations are given as 2\({x}\) + \({y}\) = 5 and 3\({x}\) + \({y}\) = 7. Find the value of \({x}\) and \({y}\).
\({x}\) = 1, \({y}\) = 2
\({x}\) = 2, \({y}\) = 1
\({x}\) = 1, \({y}\) = 1
Two simultaneous equations are given as: 6\({x}\) – 2\({y}\) = 15 and 4\({x}\) + 3\({y}\) = –3.
Which of the following cannot be used to solve the equations?
12\({x}\) – 4\({y}\) = 30 and 12\({x}\) + 9\({y}\) = –9
12\({x}\) – 6\({y}\) = 36 and 4\({x}\) + 6\({y}\) = 3
18\({x}\) – 6\({y}\) = 45 and 8\({x}\) + 6\({y}\) = –6
The cost of 2 sandwiches and a juice is £3.40. The cost of 4 sandwiches and 3 juices is £7.20. Which simultaneous equations show this information?
2s + 4s = 3.40 and j + 3j = 7.20
2s + j = 7.2 and 4s + 3j = 3.4
4s + 3j = 7.2 and 2s + j = 3.4
The cost of 2 sandwiches and a juice is £3.40. The cost of 4 sandwiches and 3 juices is £7.20. What is the cost of a juice?
£0.50
£0.40
£0.30
The cost of 2 sandwiches and a juice is £3.40. The cost of 4 sandwiches and 3 juices is £7.20. What is the cost of a sandwich?
£1
£1.25
£1.50
Two simultaneous equations are given as \({y}\) = \({x}\) + 4 and \({y}\) = \({x^2}\) + 4\({x}\).
Which of these are not a solution point for the equations?
\({x}\) = –1 and \({y}\) = 3
\({x}\) = –4 and \({y}\) = 0
\({x}\) = 1 and \({y}\) = 5
Look at the diagram below. What is the solution point for the graph?
\({x}\) = 2, \({y}\) = 3
\({x}\) = –1, \({y}\) = 2
How can you rearrange 4\({x}\) + 2\({y}\) = 6 into the form \({y}\) = m\({x}\) + c?
\({y}\) = –2\({x}\) + 3
\({y}\) = 2\({x}\) + 3
\({y}\) = 4\({x}\) + 6
Two graphs are given as \({y}\) = 0.5\({x}\) and \({y}\) = 2\({x}\) – 6. Either by plotting the graphs or otherwise, find the values of \({x}\) and \({y}\). The first graph is plotted for you on the diagram below.
\({x}\) = –4, \({y}\) = 2
\({x}\) = 4, \({y}\) = 2
\({x}\) = 4, \({y}\) = –2