Solve \({3.2y}~=~{16}\)
\[{y}~=~{51.2}\]
\[{y}~=~{12.8}\]
\[{y}~=~{5}\]
Solve \({z}~–~{5.4}~=~{10.8}\)
16.2
2
5.4
Solve \({3x}~–~{6}~=~{21}\)
\[{x}~=~{5}\]
\[{x}~=~{9}\]
\[{x}~=~{81}\]
Solve \(\frac{2y}{3}+{2}={12}\)
\[{y}={15}\]
\[{y}={20}\]
\[{y}={21}\]
A rectangle has one side of length \({z}~–~{4}\) and a second side of length 9. Write an expression for the area of the rectangle.
\[{9z}~–~{4}\]
\[{9z}~–~{36}\]
\[{2z}~+~{10}\]
Work out an expression for the area of the shape below. You should give your answer in its simplest form.
\[{20x}+{8}\]
\[{20x}+{20}\]
\[{20x}+{64}\]
Make \({p}\) the subject of the formula \({3p}~+~{2}~=~{ab}\)
\[{p}={ab}-\frac{2}{3}\]
\[{p}=\frac{ab-2}{3}\]
\[{p}=\frac{ab}{3}~-~{2}\]
Make \({r}\) the subject of the formula \(\frac{3b}{r}={s}^{2}\)
\[{r}=\frac{3b}{{s}^{2}}\]
\[{r}=\frac{{s}^{2}}{3b}\]
\[{r}=\frac{{3s}^{2}}{b}\]
Make \({q}\) the subject of the formula \({4}\sqrt{q}={12a}\)
\[{q}={3a}\]
\[{q}={9a}\]
\[{q}={9a}^{2}\]
The equation \({x}^{3}+{x}^{2}-{10}={40}\) has a solution between 3 and 4. Use a trial and improvement strategy to find this solution correct to one decimal place.
3.2
3.3
3.4