Trigonometric relationships in right-angled triangles - Int & H test questions - GCSE Maths Numeracy (WJEC) Revision

1

Which side is the hypotenuse?

Right-angled triangle with sides a, b, and c, where c is the hypotenuse

\[{a}\]

\[{b}\]

\[{c}\]

2

Which side is adjacent to the drawn angle?

Right-angled triangle with sides a, b, and c. The angle AC is highlighted

\[{a}\]

\[{b}\]

\[{c}\]

3

Which side is opposite the drawn angle?

\[{a}\]

\[{b}\]

\[{c}\]

4

Which trigonometric function could you use to calculate the missing angle?

A right-angled triangle where the hypotenuse equals 5 cm. The length of the short side equals 3 cm. The angle opposite the short side is highlighted

sin

cos

tan

5

Which trigonometric function could you use to calculate side \({x}\)?

A right-angled triangle where the hypotenuse is unknown. The short side is labelled x, and the long side equals 6 cm. The angle opposite to side x equals 24 degrees

sin

cos

tan

6

Which trigonometric function would you use to calculate the side labelled \({y}\)?

A right-angled triangle where the hypotenuse equals 5 cm. The long side is labelled y, and the short side is unknown. The angle adjacent to side y equals 35 degrees

sin

cos

tan

7

Which would be the correct calculation to work out the side marked \({y}\)?

A right-angled triangle where the hypotenuse equals 10 cm. The short side is labelled y, and the long side is unknown. The angle opposite side y equals 25 degrees

\[{10}\times{sin~25°}\]

\[\frac {10} {sin~25°}\]

\[\frac {sin~25°} {10}\]

8

Which calculation would correctly calculate the side labelled \({y}\)?

A right-angled triangle where the hypotenuse is labelled y. The long side equals 9 cm, and the short side is unknown. The angle opposite the short side equals 35 degrees

\[{9}~{cos~20°}\]

\[\frac{9} {cos~20°}\]

\[\frac{cos~20°}{9}\]

9

Which equation would correctly allow you to calculate the angle \({x}\)?

A right-angled triangle where the hypotenuse equals 20. The angle x is highlighted. The side opposite x equals 14

sin^-1 \((\frac{20}{14})\)

sin^-1 \(\frac{14}{20}\)

cos^-1 \(\frac{20}{14}\)

10

Which equation would correctly allow you to calculate the angle \({x}\)?

A right-angled triangle where the long side equals 8 and the short side equals 6. The angle opposite the long side is labelled x

tan^-1 \(~\frac{6}{8}\)

tan^-1 \(~\frac{8}{6}\)

\({6}\) tan^-1 \({8}\)