Amnewidia \({y}\) = 4 yn yr hafaliad canlynol: 4\({x}\) + 2\({y}\) = 52. Beth yw gwerth \({x}\)?
\({x}\) = 11
\({x}\) = 10
\({x}\) = 9
Rhoddir dau hafaliad cydamserol fel 2\({x}\) + \({y}\) = 5 a 3\({x}\) + \({y}\) = 7. Canfydda werth \({x}\) ac \({y}\).
\({x}\) = 1, \({y}\) = 2
\({x}\) = 2, \({y}\) = 1
\({x}\) = 1, \({y}\) = 1
Rhoddir dau hafaliad cydamserol fel: 6\({x}\) – 2\({y}\) = 15 a 4\({x}\) + 3\({y}\) = –3.
Pa rai o’r canlynol allwn ni ddim eu defnyddio i ddatrys yr hafaliadau?
12\({x}\) – 4\({y}\) = 30 a 12\({x}\) + 9\({y}\) = –9
12\({x}\) – 6\({y}\) = 36 a 4\({x}\) + 6\({y}\) = 3
18\({x}\) – 6\({y}\) = 45 a 8\({x}\) + 6\({y}\) = –6
Mae dwy frechdan a sudd yn costio £3.40. Mae pedair brechdan a thri sudd yn costio £7.20. Pa hafaliadau cydamserol sy’n dangos yr wybodaeth hon?
2b + 4b = 3.40 a s + 3s = 7.20
2b + s = 7.2 a 4b + 3s = 3.4
4b + 3s = 7.2 a 2b + s = 3.4
Mae dwy frechdan a sudd yn costio £3.40. Mae pedair brechdan a thri sudd yn costio £7.20. Beth yw cost sudd?
£0.50
£0.40
£0.30
Mae dwy frechdan a sudd yn costio £3.40. Mae pedair brechdan a thri sudd yn costio £7.20. Canfydda gost brechdan.
£1
£1.25
£1.50
Rhoddir dau hafaliad cydamserol fel \({y}\) = \({x}\) + 4 a \({y}\) = \({x^2}\) + 4\({x}\).
Pa un o’r rhain sydd ddim yn bwynt ateb ar gyfer yr hafaliadau?
\({x}\) = –1 a \({y}\) = 3
\({x}\) = –4 a \({y}\) = 0
\({x}\) = 1 a \({y}\) = 5
Edrycha ar y diagram isod. Beth yw’r pwynt ateb ar gyfer y graff?
\({x}\) = 2, \({y}\) = 3
\({x}\) = –1, \({y}\) = 2
Sut galli di ad-drefnu 4\({x}\) + 2\({y}\) = 6 i’r ffurf \({y}\) = m\({x}\) + c?
\({y}\) = –2\({x}\) + 3
\({y}\) = 2\({x}\) + 3
\({y}\) = 4\({x}\) + 6
Rhoddir dau graff fel \({y}\) = 0.5\({x}\) ac \({y}\) = 2\({x}\) – 6. Naill ai drwy blotio’r graffiau, neu fel arall, canfydda werthoedd \({x}\) ac \({y}\). Mae’r graff cyntaf wedi ei blotio i ti ar y diagram isod.
\({x}\) = –4, \({y}\) = 2
\({x}\) = 4, \({y}\) = 2
\({x}\) = 4, \({y}\) = –2