Solve the following quadratic equation correct to 2 decimal places:
\[2{x^2} + 3x - 1 = 0\]
\[x = - 0.28\,and\,x = - 1.78\]
\[x = - 0.28\,and\,x = 1.78\]
\[x = 0.28\,and\,x = - 1.78\]
\[3{x^2} + 8x + 1 = 0\]
\[x = - 0.13\,and\,x = - 2.54\]
\[x = - 0.13\,and\,x = 2.54\]
\[x = 0.13\,and\,x = - 2.54\]
\[10{x^2} + x - 1 = 0\]
\[x = - 0.27\,and\,x = - 0.37\]
\[x = - 0.27\,and\,x = 0.37\]
\[x = 0.27\,and\,x = - 0.37\]
\[3 + 4x - {x^2} = 0\]
\[x = - 0.65\,and\,x = - 4.65\]
\[x = - 0.65\,and\,x = 4.65\]
\[x = 0.65\,and\,x = - 4.65\]
Solve 2x2 - 7x - 7 = 0, leaving the answer in surd (square root) form.
\[x = \frac{7 \pm \sqrt{105}}{4}\]
\[x = \frac{7 \pm \sqrt{105}}{2}\]
\[x = \frac{-7 \pm \sqrt{105}}{4}\]