Expand (x – 2)(x + 4)
x2 + 2x - 8
x2 + 6x - 8
x2 + 6x + 8
Expand (x – 4)(x – 6)
x2 – 10x – 24
x2 + 10x – 24
x2 – 10x + 24
Factorise x2 – 9x + 20
(x - 4)(x - 5)
(x – 8)(x – 1)
(x + 6.5)(x – 14.5)
Factorise x2 + 4x – 21
(x – 7)(x + 3)
(x + 7)(x – 3)
(x – 7)(x – 3)
Factorise 9x2 – 25
(9x – 5)(9x + 5)
(3x – 5)(3x + 5)
(4.5x – 5)(4.5x + 5)
Factorise 3x2 – 14x – 5
(3x – 5)(x + 1)
(3x + 5)(x – 1)
(3x + 1)(x – 5)
Two rectangles of area x2 + 2x – 3 are joined together. Which of the following pairs could represent the lengths of the sides of the new shape?
(x – 1), (x + 3)
(2x – 2), (x + 3)
(x – 1), (2x + 3)
Solve x2 + 17x + 16 = 0 by factorising.
x = 1 and x = 16
x = –1 and x = –16
x = 1 and x = –16
Solve x2 – 4x + 2 = 0 using the quadratic formula.
x = –0.586 and x = –3.313
x = –0.586 and x = 3.414
x = 0.586 and x = 3.414
This is the graph of y = x2 – 5x – 20:
Use the graph to solve x2 – 5x – 20 = 0.
(x = –2.5) , (x = 7.5)
(x = –2.1) , (x = 6.4)
(x = –2.2) , (x = 6.8)